DataFrame.
update
Modify in place using non-NA values from another DataFrame.
Aligns on indices. There is no return value.
Should have at least one matching index/column label with the original DataFrame. If a Series is passed, its name attribute must be set, and that will be used as the column name to align with the original DataFrame.
Only left join is implemented, keeping the index and columns of the original object.
How to handle non-NA values for overlapping keys:
True: overwrite original DataFrame’s values with values from other.
False: only update values that are NA in the original DataFrame.
Can choose to replace values other than NA. Return True for values that should be updated.
If ‘raise’, will raise a ValueError if the DataFrame and other both contain non-NA data in the same place.
Changed in version 0.24.0: Changed from raise_conflict=False|True to errors=’ignore’|’raise’.
When errors=’raise’ and there’s overlapping non-NA data.
When errors is not either ‘ignore’ or ‘raise’
If join != ‘left’
See also
dict.update
Similar method for dictionaries.
DataFrame.merge
For column(s)-on-columns(s) operations.
Examples
>>> df = pd.DataFrame({'A': [1, 2, 3], ... 'B': [400, 500, 600]}) >>> new_df = pd.DataFrame({'B': [4, 5, 6], ... 'C': [7, 8, 9]}) >>> df.update(new_df) >>> df A B 0 1 4 1 2 5 2 3 6
The DataFrame’s length does not increase as a result of the update, only values at matching index/column labels are updated.
>>> df = pd.DataFrame({'A': ['a', 'b', 'c'], ... 'B': ['x', 'y', 'z']}) >>> new_df = pd.DataFrame({'B': ['d', 'e', 'f', 'g', 'h', 'i']}) >>> df.update(new_df) >>> df A B 0 a d 1 b e 2 c f
For Series, it’s name attribute must be set.
>>> df = pd.DataFrame({'A': ['a', 'b', 'c'], ... 'B': ['x', 'y', 'z']}) >>> new_column = pd.Series(['d', 'e'], name='B', index=[0, 2]) >>> df.update(new_column) >>> df A B 0 a d 1 b y 2 c e >>> df = pd.DataFrame({'A': ['a', 'b', 'c'], ... 'B': ['x', 'y', 'z']}) >>> new_df = pd.DataFrame({'B': ['d', 'e']}, index=[1, 2]) >>> df.update(new_df) >>> df A B 0 a x 1 b d 2 c e
If other contains NaNs the corresponding values are not updated in the original dataframe.
>>> df = pd.DataFrame({'A': [1, 2, 3], ... 'B': [400, 500, 600]}) >>> new_df = pd.DataFrame({'B': [4, np.nan, 6]}) >>> df.update(new_df) >>> df A B 0 1 4.0 1 2 500.0 2 3 6.0