numpy.char.count#

char.count(a, sub, start=0, end=None)[source]#

Returns an array with the number of non-overlapping occurrences of substring sub in the range [start, end].

Calls str.count element-wise.

Parameters

aarray_like of str or unicode
substr or unicode: The substring to search for.
start, endint, optional: Optional arguments start and end are interpreted as slice notation to specify the range in which to count.

Returns

outndarray: Output array of ints.

See also

str.count

Examples

>>> c = np.array(['aAaAaA', '  aA  ', 'abBABba'])
>>> c
array(['aAaAaA', '  aA  ', 'abBABba'], dtype='<U7')
>>> np.char.count(c, 'A')
array([3, 1, 1])
>>> np.char.count(c, 'aA')
array([3, 1, 0])
>>> np.char.count(c, 'A', start=1, end=4)
array([2, 1, 1])
>>> np.char.count(c, 'A', start=1, end=3)
array([1, 0, 0])

numpy.char.compare_chararrays

numpy.char.endswith